TS EAMCET · Maths · Complex Number
If \(\alpha, \beta\) are the roots of the equation \(x^2-4 x+8=0\), then for any \(n \in N, \alpha^{2 n}+\beta^{2 n}\) equals
- A \(2^{2 n+1} \cos \frac{n \pi}{2}\)
- B \(2^{3 n} \cos \frac{n \pi}{2}\)
- C \(2^{3 n+1} \cos \frac{n \pi}{2}\)
- D \(2^{3 n} \cos \frac{n \pi}{4}\)
Answer & Solution
Correct Answer
(C) \(2^{3 n+1} \cos \frac{n \pi}{2}\)
Step-by-step Solution
Detailed explanation
Since, \(\alpha, \beta\) are the roots of the equation…
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