TS EAMCET · Maths · Binomial Theorem
For \(x=\frac{5}{7}\), if \(t_k\) is the first negative term in the expansion of \((1+x)^{7 / 5}\), then, \(t_1+t_2+\ldots+t_k=\)
- A \(\frac{13}{7}\)
- B \(\frac{107}{14}\)
- C \(\frac{104}{49}\)
- D \(\frac{921}{28}\)
Answer & Solution
Correct Answer
(C) \(\frac{104}{49}\)
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