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TS EAMCET · Maths · Differentiation

\(\frac{d}{d x} \tan ^{-1}\left[\frac{\sqrt{1+\sin x}-\sqrt{1-\sin x}}{\sqrt{1+\sin x}+\sqrt{1-\sin x}}\right]\) is equal to

  1. A 1
  2. B \(-\frac{1}{2}\)
  3. C \(\frac{1}{2}\)
  4. D -1
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { Let } y=\tan ^{-1}\left[\frac{\sqrt{1+\sin x}-\sqrt{1-\sin x}}{\sqrt{1+\sin x}+\sqrt{1-\sin x}}\right] \\ & =\tan ^{-1}\left[\frac{\left(\sin \frac{x}{2}+\cos \frac{x}{2}\right)-\left(\cos \frac{x}{2}-\sin \frac{x}{2}\right)}{\left(\sin \frac{x}{2}+\cos…