TS EAMCET · Maths · Indefinite Integration
If \(f(x)=\int \frac{2-3 \sin ^2 x}{1+\cos 2 x} d x\) and \(f\left(\frac{\pi}{4}\right)=1\) then \(f(0)=\)
- A \(\frac{3}{8}(4-\pi)\)
- B \(3-\frac{\pi}{4}\)
- C 0
- D 1
Answer & Solution
Correct Answer
(A) \(\frac{3}{8}(4-\pi)\)
Step-by-step Solution
Detailed explanation
We have \(f(x)=\int \frac{2-3 \sin ^2(x)}{1+\cos ^2(2 x)} d x\) and given \(\mathrm{f}\left(\frac{\pi}{4}\right)=1\) now \(f(x)=\int \frac{3-3 \sin ^2(x)-1}{2 \cos ^2(x)} d x\) \(f(x)=\frac{3}{2} x-\frac{1}{2} \tan (x)+c\) now \(\mathrm{f}\left(\frac{\pi}{4}\right)=1\)…
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