TS EAMCET · Physics · Nuclear Physics
If \(96.875 \%\) of a radioactive substance decays in 10 days, then the half life of the substance is (in days)
- A \(10\)
- B \(5\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
\(N/N_0 = 1 - 0.96875 = 0.03125\) \(0.03125 = (1/2)^{10/T_{1/2}}\) \((1/2)^5 = (1/2)^{10/T_{1/2}}\) \(5 = 10/T_{1/2}\) \(T_{1/2} = 10/5 = 2\) days
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