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TS EAMCET · Maths · Limits

\(\lim _{x \rightarrow \infty}\left(\frac{2 x^2+3 x+4}{x^2-3 x+5}\right)^{\frac{3|x|+1}{2|x|-1}}=\)

  1. A \(\frac{3}{2}\)
  2. B \(2 \sqrt{2}\)
  3. C 3
  4. D \(\sqrt{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2 \sqrt{2}\)

Step-by-step Solution

Detailed explanation

Let \(L=\lim _{x \rightarrow \infty}\left(\frac{2 x^2+3 x+4}{x^2-3 x+5}\right)^{\frac{3|x|+1}{|x|-1}}\)…