TS EAMCET · Maths · Three Dimensional Geometry
If a plane \(\pi\) passes through the point \((-1,6,2)\) is perpendicular to the planes \(x+2 y+2 z-5=0\) and \(3 x+3 y+2 z-8=0\), then, the perpendicular distance from the point \((1,-1,1)\) to the plane \(\pi\) is
- A \(\frac{20}{\sqrt{29}}\)
- B \(\frac{21}{\sqrt{29}}\)
- C \(\frac{27}{\sqrt{29}}\)
- D \(\sqrt{29}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{29}\)
Step-by-step Solution
Detailed explanation
Equation of plane passing through the point \((-1,6,2)\) and perpendicular to planes \(x+2 y+2 z-5=0\) and \(3 x+3 y+2 z-8=0\) is \(\left|\begin{array}{ccc} x+1 & y-6 & z-2 \\ 1 & 2 & 2 \\ 3 & 3 & 2 \end{array}\right|=0\)…
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