TS EAMCET · Maths · Parabola
Match the points on the curve \(2 y^2=x+1\) with the slopes of normals at those points and choose the correct answer. 
- A \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \ 2 & 4 & 3 & 1\end{array}\)
- B \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \ 2 & 5 & 3 & 1\end{array}\)
- C \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \ 2 & 3 & 5 & 1\end{array}\)
- D \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \ 2 & 5 & 1 & 3\end{array}\)
Answer & Solution
Correct Answer
(B) \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D } \ 2 & 5 & 3 & 1\end{array}\)
Step-by-step Solution
Detailed explanation
Given equation of curve is \[ 2 y^2=x+1 \] On differentiating both sides w.r.t. \(x\), we get \[ \text { 4y } \frac{d y}{d x}=1 \Rightarrow \frac{d y}{d x}=\frac{1}{4 y} \] \(\therefore\) The slope of the normal is \[ \frac{d x}{d y}=-4 y \] I.…
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