TS EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{2 \sin x-\sin 2 x}{x^3}\) is equal to
- A 1
- B 0
- C -1
- D does not exist
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Let \(L=\lim _{x \rightarrow 0} \frac{2 \sin x-\sin 2 x}{x^3}\left(\right.\) form \(\left.\frac{0}{0}\right)\) (using L-Hospital rule)…
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