TS EAMCET · Maths · Quadratic Equation
Suppose, \(\alpha\) is minimum value of \(x^2+b x+5\) and \(\beta\) is maximum value of \(-x^2+a x+5\). If \([\alpha, \beta]\) is the interval of maximum length for \(x\) in which \(x^2-10 x+24 \leq 0\), then \(a^2 b^2\) is equal to
- A 25
- B 16
- C 4
- D 18
Answer & Solution
Correct Answer
(B) 16
Step-by-step Solution
Detailed explanation
From given question, we observe that \(\alpha\) occurs at \(x=\frac{-b}{2 a}\) i.e. \(x=\frac{-b}{2}\) and \(\beta\) occurs at \(x=\frac{-b}{2 a}\), i.e. \(x=\frac{+a}{2}\) So,…
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