TS EAMCET · Maths · Probability
If \(A\) and \(B\) are two independent events such that \(P(B)=\frac{2}{7}\) and \(P\left(A \cup B^C\right)=0.8\), then \(P(A \cup B)\) \(=\)
- A \(\frac{29}{35}\)
- B \(\frac{39}{70}\)
- C \(\frac{1}{2}\)
- D \(\frac{41}{105}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
We have, \(P(A \cap B)=P(A) . P(B), P(B)=\frac{2}{7}\). and \[ P\left(A \cup B^c\right)=0.8 \] Consider, \(P\left(A \cup B^c\right)=0.8\)…
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