TS EAMCET · Maths · Circle
If the circles \(x^2+y^2-2 \lambda x-2 y-7=0\) and \(3\left(x^2+y^2\right)-8 x+29 y=0\) are orthogonal, then \(\lambda\) is equal to
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
The equation of the circle are \[ \begin{array}{r} x^2+y^2-2 \lambda x-2 y-7=0 \\ 3\left(x^2+y^2\right)-8 x+29 y=0 \\ x^2+y^2-\frac{8}{3} x+\frac{29}{3} y=0 \end{array} \] On comparing Eq. (i) and Eq. (ii) with…
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