TS EAMCET · Maths · Mathematical Induction
Using mathematical induction, the numbers \(a_n\) 's are defined by, \(a_0=1, a_{n+1}=3 n^2+n+a_n,(n \geq 0) .\) Then, \(a_n\) is equal to
- A \(n^3+n^2+1\)
- B \(n^3-n^2+1\)
- C \(n^3-n^2\)
- D \(n^3+n^2\)
Answer & Solution
Correct Answer
(B) \(n^3-n^2+1\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { Given, } a_0=1, a_{n+1}=3 n^2+n+a_n \\ & \Rightarrow \quad a_1=3(0)+0+a_0=1 \\ & \text { and } \quad a_2=3(1)^2+1+a_1=3+1+1=5 \end{aligned}\) From option (b),…
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