TS EAMCET · Maths · Vector Algebra
If \(2 \bar{i}+4 \bar{j}-5 \bar{k}, \bar{i}+\bar{j}+\bar{k}, \bar{j}+2 \bar{k}\) are the position vectors of the vertices A, B, C of a triangle respectively, then a unit vector along the median drawn through the vertex \(\mathrm{A}\) is
- A \(\frac{1}{\sqrt{174}}(5 \bar{i}+10 \bar{j}-7 \bar{k})\)
- B \(\frac{1}{\sqrt{214}}(3 \bar{i}+6 \bar{j}-13 \bar{k})\)
- C \(\frac{1}{\sqrt{66}}(\bar{i}+\bar{j}-8 \bar{k})\)
- D \(\frac{1}{7}(3 \bar{i}+6 \bar{j}-2 \bar{k})\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{\sqrt{214}}(3 \bar{i}+6 \bar{j}-13 \bar{k})\)
Step-by-step Solution
Detailed explanation
Given three position vectors of the verticses of triangle \(A, B, C\) are \(2 \hat{i}+4 \hat{j}-5 \hat{k}, \hat{i}+\hat{y}+\hat{k}\) and \(\hat{i}+2 \hat{k}\) respectively.…
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