ExamBro
ExamBro
TS EAMCET · Maths · Differentiation

If \(\left(x^2-3 x+2\right) e^{\frac{y}{x-1}}=x+2\) then \(\left(\frac{d y}{d x}\right)_{x=0}=\)

  1. A \(2\)
  2. B \(-2\)
  3. C \(1\)
  4. D \(-1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-2\)

Step-by-step Solution

Detailed explanation

\( (0^2-3(0)+2)e^{\frac{y}{0-1}}=0+2 \implies 2e^{-y}=2 \implies e^{-y}=1 \implies y=0 \) \(\frac{d}{dx}\left[\left(x^2-3 x+2\right) e^{\frac{y}{x-1}}\right]=\frac{d}{dx}(x+2)\)…