TS EAMCET · Maths · Definite Integration
\(\int_{-2}^4\left|2-x^2\right| d x=\)
- A \(\frac{8 \sqrt{2}}{3}-3\)
- B \(\frac{16 \sqrt{2}}{3}+12\)
- C \(\frac{16 \sqrt{2}}{3}-3\)
- D \(\frac{8 \sqrt{2}}{3}+12\)
Answer & Solution
Correct Answer
(B) \(\frac{16 \sqrt{2}}{3}+12\)
Step-by-step Solution
Detailed explanation
\( \int_{-2}^4|2-x^2| dx = \int_{-2}^{-\sqrt{2}}(x^2-2) dx + \int_{-\sqrt{2}}^{\sqrt{2}}(2-x^2) dx + \int_{\sqrt{2}}^4(x^2-2) dx \)…
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