TS EAMCET · Physics · Electrostatics
In a regular polygon of 10 sides, each corner is at a distance \(R\) from the centre. Identical charges are placed at 9 corners. At the centre, the magnitude of electric field is \(E\) and the potential is \(V\). The ratio \(\frac{V}{E}\) is
- A \(10 R\)
- B \(\frac{9}{R}\)
- C \(\frac{9}{10} R\)
- D \(9 R\)
Answer & Solution
Correct Answer
(D) \(9 R\)
Step-by-step Solution
Detailed explanation
Since electric potential is a scalar quantity. So, the potential at the centre is given as \(V=K \frac{q}{R}+K \frac{q}{R}+\ldots .9 \text { times }\) \(V=\frac{9 K q}{R}\)....(i) Since, electric field is a vector quantity. So, the electric field cancel each other for the…
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