TS EAMCET · Maths · Circle
If \(\frac{2}{\sqrt{5}}\) is the length of the common chord of the circles \(x^2+y^2+2 x+2 y+1=0\) and \(x^2+y^2+\alpha x+3 y+2=0, \alpha \neq 0\), then \(\alpha=\)
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(A) 4
Step-by-step Solution
Detailed explanation
Equation of common chord \(=S_1-S_2=0\) \[ \begin{array}{r} {\left[x^2+y^2+2 x+2 y+1\right]-\left[x^2+y^2+\alpha x+3 y+2\right]=0} \\ (2-\alpha) x-y-1=0 \end{array} \] Length of common chord \(=2 \sqrt{r^2-p^2}\)…
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