TS EAMCET · Maths · Indefinite Integration
If \(\int \frac{x^2\left(x \sec ^2 x+\tan x\right)}{(x \tan x+1)^2} d x=A \log\) \((|x \sin x+\cos x|)+B \frac{f(x)}{(x \tan x+1)}+C\), then \(f(A+B)=\)
- A 1
- B 0
- C -1
- D 2
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Let \(I=\int x^2 \cdot \frac{x \sec ^2 x+\tan x}{(x \tan x+1)^2} d x\) \(=x^2\left(-\frac{1}{(x \tan x+1)}\right)-\int 2 x\left(-\frac{1}{(x \tan x+1}\right) d x\) \(\left[\right.\) since…
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