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TS EAMCET · Maths · Circle

\(x^2+y^2+2 x-6 y-6=0\) and \(x^2+y^2-6 x-2 y+k=0\) are two intersecting circles and \(k\) is not an integer. If \(\theta\) is the angle between the two circles and \(\cos \theta=\frac{-5}{24}\), then \(k=\)

  1. A \(\frac{6}{5}\)
  2. B \(\frac{74}{9}\)
  3. C \(\frac{37}{3}\)
  4. D \(\frac{53}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{74}{9}\)

Step-by-step Solution

Detailed explanation

\(x^2+y^2+2 x-6 y-6=0\) \(C_1\) : Centre \((-1,3)\), Radius \(=4\) \(x^2+y^2-6 x-2 y+k=0\) \(C_2\) : Centre \((3,1)\), Radius \(=\sqrt{10-k}\)…