TS EAMCET · Maths · Circle
\(x^2+y^2+2 x-6 y-6=0\) and \(x^2+y^2-6 x-2 y+k=0\) are two intersecting circles and \(k\) is not an integer. If \(\theta\) is the angle between the two circles and \(\cos \theta=\frac{-5}{24}\), then \(k=\)
- A \(\frac{6}{5}\)
- B \(\frac{74}{9}\)
- C \(\frac{37}{3}\)
- D \(\frac{53}{7}\)
Answer & Solution
Correct Answer
(B) \(\frac{74}{9}\)
Step-by-step Solution
Detailed explanation
\(x^2+y^2+2 x-6 y-6=0\) \(C_1\) : Centre \((-1,3)\), Radius \(=4\) \(x^2+y^2-6 x-2 y+k=0\) \(C_2\) : Centre \((3,1)\), Radius \(=\sqrt{10-k}\)…
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