TS EAMCET · Maths · Circle
Given the circle \(C\) with the equation \(x^2+y^2-2 x+10 y-38=0\). Match the List I with the List II given below concerning \(C\) 
The correct answer is \(\begin{array}{llll}\text { A } & \text { B } & \text { C } & \text { D }\end{array}\)
- A \(\begin{array}{llll}\text { III } & \text { I } & \text { V } & \text { II }\end{array}\)
- B \(\begin{array}{llll}\text { IV } & \text { V } & \text { I } & \text { II }\end{array}\)
- C \(\begin{array}{llll}\text { III } & \text { V } & \text { I } & \text { II }\end{array}\)
- D \(\begin{array}{llll}\text { IV } & \text { II } & \text { I } & \text { V }\end{array}\)
Answer & Solution
Correct Answer
(C) \(\begin{array}{llll}\text { III } & \text { V } & \text { I } & \text { II }\end{array}\)
Step-by-step Solution
Detailed explanation
Given equation of circle is \(x^2+y^2-2 x+10 y-38=0\) (A) Polar equation at point \((4,3)\) is \(S_1=0\). \(\begin{aligned} & \Rightarrow \quad x \times 4+y \times 3-(x+4) \\ & \quad+5(y+3)-38=0 \\ & \Rightarrow \quad 3 x+8 y=27\end{aligned}\) (B) Equation of tangent at point…
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