TS EAMCET · Maths · Three Dimensional Geometry
In a quadrilateral \(A B C D\), the point \(P\) divides \(D C\) in the ratio \(1: 2\) and \(Q\) is the mid point of \(A C\). If \(\overrightarrow{\mathbf{A B}}+2 \overrightarrow{\mathbf{A D}}+\overrightarrow{\mathbf{B C}}-2 \overrightarrow{\mathbf{D C}}=k \overrightarrow{\mathbf{P Q}}\), then \(k\) is equal to
- A -6
- B -4
- C 6
- D 4
Answer & Solution
Correct Answer
(A) -6
Step-by-step Solution
Detailed explanation
Now, \(\overrightarrow{\mathbf{A B}}+2 \overrightarrow{\mathbf{A D}}+\overrightarrow{\mathbf{B C}}-2 \overrightarrow{\mathbf{D C}}\) \(=\overrightarrow{\mathbf{A C}}+2 \overrightarrow{\mathbf{A D}}-2 \overrightarrow{\mathbf{D C}}\)…
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