TS EAMCET · Maths · Differentiation
If \(x=2 \sqrt{2} \sqrt{\cos 2 \theta}\) and \(y=2 \sqrt{2} \sqrt{\sin 2 \theta}, 0 < \theta < \frac{\pi}{4}\) then the value of \(\frac{d y}{d x}\) at \(\theta=22 \frac{1}{2}^{\circ}\) is
- A \(1\)
- B \(-1\)
- C \(0\)
- D \(\sqrt{3}\)
Answer & Solution
Correct Answer
(B) \(-1\)
Step-by-step Solution
Detailed explanation
\(\frac{dx}{d\theta} = 2 \sqrt{2} \cdot \frac{1}{2} (\cos 2 \theta)^{-1/2} (-\sin 2 \theta) (2) = -2 \sqrt{2} \frac{\sin 2 \theta}{\sqrt{\cos 2 \theta}}\)…
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