TS EAMCET · Maths · Straight Lines
If the line \(3 x+4 y+\lambda=0\) divides the distance between the lines \(3 x+4 y+5=0\) and \(3 x+4 y-5=0\) in the ratio of \(3: 7\), then a value of \(\lambda\) is
- A \(-2\)
- B \(2\)
- C \(0\)
- D \(5\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
According to the given informations, \(\frac{\frac{|\lambda-5|}{\sqrt{3^2+4^2}}}{\frac{|\lambda+5|}{\sqrt{3^2+4^2}}}=\frac{3}{7} \Rightarrow \frac{|\lambda-5|}{|\lambda+5|}=\frac{3}{7}\)…
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