TS EAMCET · Maths · Definite Integration
Dividing the interval \([0,6]\) into 6 equal parts and by using trapezoidal rule the value of \(\int_0^6 x^3 d x\) is approximately :
- A 330
- B 331
- C 332
- D 333
Answer & Solution
Correct Answer
(D) 333
Step-by-step Solution
Detailed explanation
By trapezoidal rule \(\int_0^6 x^3 d x=\frac{h}{2}\left\{y_0+y_6+2\left(y_1+y_2\right.\right.\) \(\left.\left.+y_3+y_4+y_5\right)\right\}\) \(=\frac{1}{2}\{0+216+2(1+8+27+64+125)\}\) \(=\frac{1}{2}\{216+450\}=\frac{666}{2}\) \(=333\)
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