TS EAMCET · Chemistry · Solutions
\(15 \%\) aqueous solution of glucose (molecular weight \(=180 \mathrm{~g} / \mathrm{mol}\) ) is isotonic with \(8 \%\) aqueous solution containing an unknown non-dissociable solute. What is the molecular weight of the unknown solute?
- A 108
- B 96
- C 84
- D 9.6
Answer & Solution
Correct Answer
(B) 96
Step-by-step Solution
Detailed explanation
Given, Molecular weight of \(15 \%\) aqueous solution of glucose \(=180 \mathrm{~g} / \mathrm{mol}\) Molecular weight of solute \(=\) ? \(\pi_1(\) glucose \()=\pi_2(\) unknown solute \()\) \(C_1(\) urea \()=C_2(\) unknown solute \()\) Now,…
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