TS EAMCET · Maths · Differentiation
\(x=\frac{1-\sqrt{y}}{1+\sqrt{y}} \Rightarrow \frac{d y}{d x}\) is equal to
- A \(\frac{4}{(x+1)^2}\)
- B \(\frac{4(x-1)}{(1+x)^3}\)
- C \(\frac{x-1}{(1+x)^3}\)
- D \(\frac{4}{(x+1)^3}\)
Answer & Solution
Correct Answer
(B) \(\frac{4(x-1)}{(1+x)^3}\)
Step-by-step Solution
Detailed explanation
Given, \(\frac{x}{1}=\frac{1-\sqrt{y}}{1+\sqrt{y}}\) Applying componendo and dividendo, we get…
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