TS EAMCET · Maths · Ellipse
If \(\mathrm{P}(\theta)\) and \(Q\left(\frac{\pi}{2}+\theta\right)\) are two points on the ellipse \(\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\) and the locus of midpoint of PQ is \(\frac{x^2}{\alpha^2}+\frac{y^2}{\beta^2}=1\), then \(\frac{a+b}{\alpha+\beta}=\)
- A \(\frac{1}{\sqrt{2}}\)
- B \(\sqrt{3}\)
- C \(\frac{1}{\sqrt{3}}\)
- D \(\sqrt{2}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
Given two points \(\mathrm{P}(\theta)\) and \(\mathrm{Q}\left(\frac{\pi}{2}+\theta\right)\) are on the ellipse. Hence, \[ \mathrm{P}=(\mathrm{a} \cos \theta, \mathrm{b} \sin \theta), \mathrm{Q}=(-\mathrm{a} \sin \theta, \mathrm{b} \cos \theta) \] now mid point of \(P Q\)…
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