TS EAMCET · Maths · Probability
A boy spcaks truth in 3 out of 5 times. If he throws a die and tells that the number appeared on it is five, then the probability that it is actually five, is
- A \(\frac{1}{3}\)
- B \(\frac{1}{10}\)
- C \(\frac{13}{30}\)
- D \(\frac{3}{13}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{13}\)
Step-by-step Solution
Detailed explanation
Let \(E_1\) : Event of getting a five \(E_2\) : Event of not getting a five and \(A\) : Event that the boy reports that it is a five. So, required probabilltv by Baye's theorem…
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