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TS EAMCET · Maths · Differential Equations

The general solution of dydx=x+sinxcosy+xcosy+sinx is

  1. A tanx2=y22-cosy+C
  2. B tany2=x22-cosx+C
  3. C sec2y2=x22-cosx+C
  4. D tany2=x22+cosx+Cx
Verified Solution

Answer & Solution

Correct Answer

(B) tany2=x22-cosx+C

Step-by-step Solution

Detailed explanation

Given dydx=x+sinxcosy+xcosy+sinx ⇒dydx=x1+cosy+sinx1+cosy ⇒dy1+cosy=x+sinxdx Integrating both sides, ⇒∫dy1+cosy=∫x+sinxdx ⇒∫dy2cos2y2=∫x+sinxdx  ∴1+cos2A=2cos2A ⇒12∫sec2y2dy=∫x+sinxdx…