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TS EAMCET · Maths · Vector Algebra

If OA¯=i¯+2j¯+3k¯ and OB¯=4i¯+k¯ are the position vectors of the points A and B, then the position vector of a point on the line passing through B and parallel to the vector OA¯×OB¯ which is at a distance of 189 units from B is

  1. A 6i^+11j^-7k^
  2. B 4i^+11j^-8k^
  3. C 2i^+11j^-8k^
  4. D -2i^-11j^+8k^
Verified Solution

Answer & Solution

Correct Answer

(A) 6i^+11j^-7k^

Step-by-step Solution

Detailed explanation

Let, C=x,y,z such that BC→ is parallel to OA→×OB→ and BC→=189. Apply BC→=λOA→×OB→ ⇒x-4i^+yj^+z-1k^=λi^j^k^123401 ⇒x-4i^+yj^+z-1k^=λ2i^+11j^-8k^ ⇒x=4+2λ, y=11λ, z=1-8λ…