TS EAMCET · Maths · Parabola
The radius of the circle which cuts all the three circles \(x^2+y^2-4 x-4 y+3=0, x^2+y^2+4 x-4 y+3=0\) and \(x^2+y^2+4 x+4 y+3=0\) orthogonally is
- A 1
- B \(\sqrt{3}\)
- C \(\sqrt{5}\)
- D \(\sqrt{7}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{3}\)
Step-by-step Solution
Detailed explanation
Given circles are \[ \begin{aligned} & x^2+y^2-4 x-4 y+3=0 \\ & x^2+y^2+4 x-4 y+3=0 \\ & x^2+y^2+4 x+4 y+3=0 \end{aligned} \] Radical axis from (i) \& (ii), \[ \begin{aligned} & x^2+y^2-4 x-4 y+3-x^2-y^2-4 x+4 y-3=0 \\ & -8 x=0 \\ & x=0 \end{aligned} \] Radical axis from (ii) \&…
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