TS EAMCET · Maths · Definite Integration
\(\int_{-\pi / 8}^{\pi / 8} \frac{\sin ^4(4 x)}{1+e^{4 x}} d x=\)
- A \(\frac{3 \pi}{128}\)
- B \(\frac{3 \pi}{256}\)
- C \(\frac{3 \pi}{64}\)
- D \(\frac{3 \pi}{32}\)
Answer & Solution
Correct Answer
(C) \(\frac{3 \pi}{64}\)
Step-by-step Solution
Detailed explanation
\(I=\int_{-\frac{\pi}{8}}^{\frac{\pi}{8}} \frac{\sin ^4(4 x)}{1+e^{4 x}} d x\)....(i) Using \(\int_a^b f(x) d x=\int_a^b f(a+b-x) d x\)…
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