TS EAMCET · Maths · Definite Integration
If \(\int_0^b \frac{d x}{1+x^2}=\int_b^{\infty} \frac{d x}{1+x^2}\), then \(b\) is equal to
- A \(\tan ^{-1}\left(\frac{1}{3}\right)\)
- B \(\frac{\sqrt{3}}{2}\)
- C \(\sqrt{2}\)
- D \(1\)
Answer & Solution
Correct Answer
(D) \(1\)
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