TS EAMCET · Chemistry · States of Matter
The van der Waals' equation for \(0.5 \mathrm{~mol}\) of a gas is
- A \(\left(p+\frac{a}{4 V^2}\right)\left(\frac{V-b}{2}\right)=R T\)
- B \(\left(p+\frac{a}{4 V^2}\right)(2 V-b)=R T\)
- C \(\left(p+\frac{a}{4 V^2}\right)(2 V-4 b)=R T\)
- D \(\left(p+\frac{a}{4 V^2}\right)=\frac{2 R T}{2(V-b)}\)
Answer & Solution
Correct Answer
(B) \(\left(p+\frac{a}{4 V^2}\right)(2 V-b)=R T\)
Step-by-step Solution
Detailed explanation
van der Waals' equation is \[ \left(p+\frac{a n^2}{V^2}\right)(V-n b)=n R T \] where, \(\quad a=\) correction in pressure \(b=\) correction in volume \(n=\) number of moles Given, \(\quad n=0.5 \mathrm{~mol}\) \[ \left(p+\frac{a(0.5)^2}{V^2}\right)(V-0.5 b)=0.5 R T \] or…
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