TS EAMCET · Chemistry · Solutions
If \(2 \mathrm{~g}\) of \(\mathrm{NaOH}\) is dissolved to make \(200 \mathrm{ml}\) solution at \(25^{\circ} \mathrm{C}\), the molarity \((\mathrm{M})\) at \(90^{\circ} \mathrm{C}\) is
- A \(\mathrm{M} < 0.25\)
- B \(0.5>M>0.25\)
- C \(\mathrm{M}=0.25\)
- D \(0.5 < \mathrm{M} < 1.0\)
Answer & Solution
Correct Answer
(A) \(\mathrm{M} < 0.25\)
Step-by-step Solution
Detailed explanation
Concentration of the solution at \(20^{\circ} \mathrm{C}\) \[ =\frac{\mathrm{n}}{\mathrm{V}}=\frac{2 / 40}{200 / 1000}=0.25(\mathrm{M}) \quad[\mathrm{Mw} \text { of } \mathrm{NaOH}=40] \] As temp. increases the volume of the solution increases but the no. of moles remains the…
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