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TS EAMCET · Maths · Continuity and Differentiability

Let \(f: R \rightarrow R\) be defined by \(f(x)=\left\{\begin{array}{ccc}\alpha+\frac{\sin [x]}{x}, & \text { if } & x>0 \ 2, & \text { if } & x=0 \ \beta+\left[\frac{\sin x-x}{x^3}\right], & \text { if } & x < 0\end{array}\right.\) where, \([x]\) denotes the integral part of \(x\). If \(f\) continuous at \(x=0\), then \(\beta-\alpha\) is equal to

  1. A \(-1\)
  2. B \(1\)
  3. C \(0\)
  4. D \(2\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1\)

Step-by-step Solution

Detailed explanation

Given. \(f(x)=\left\{\begin{array}{lll}\alpha+\frac{\sin [x]}{x}, & \text { if } & x>0 \\ 2, & \text { if } & x=0 \\ \beta+\left[\frac{\sin x-x}{x^3}\right], & \text { if } & x < 0\end{array}\right.\) Since, \(f\) is continuous at \(x=0\). \(\therefore \mathrm{IHI}=f(0)=\) RHI.…