TS EAMCET · Chemistry · Structure of Atom
The radius of stationary state \((n=2)\) of hydrogen atom is \(x \mathrm{pm}\). The radius of stationary state \((n=3)\) of \(\mathrm{He}^{+}\)ion (in pm) is
- A \(\frac{9}{8 x}\)
- B \(\frac{9 x}{8}\)
- C \(\frac{16 x}{9}\)
- D \(\frac{9}{16 x}\)
Answer & Solution
Correct Answer
(B) \(\frac{9 x}{8}\)
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