TS EAMCET · Chemistry · Carboxylic Acid Derivatives
The sequence of reagents which convert p-methyl aniline to p-methyl benzoic acid are
- A \(\mathrm{KMnO}_4 / \mathrm{H}^{+} ; \mathrm{NaNO}_2+\mathrm{HCl} ; \mathrm{Cu} / \mathrm{HCl}\)
- B \(\mathrm{NaNO}_2+\mathrm{HCl} / 273 \mathrm{~K} ; \mathrm{Cu} / \mathrm{HCl} ; \mathrm{KMnO}_4 / \mathrm{H}^{+}\)
- C \(\mathrm{NaNO}_2+\mathrm{HCl} / 273 \mathrm{~K} ; \mathrm{CuCN} / \mathrm{KCN} ; \mathrm{H}_3 \mathrm{O}^{+}\)
- D \(\mathrm{NaNO}_2+\mathrm{HCl} / 285 \mathrm{~K} ; \mathrm{KCN} ; \mathrm{H}_3 \mathrm{O}^{+}\)
Answer & Solution
Correct Answer
(C) \(\mathrm{NaNO}_2+\mathrm{HCl} / 273 \mathrm{~K} ; \mathrm{CuCN} / \mathrm{KCN} ; \mathrm{H}_3 \mathrm{O}^{+}\)
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