TS EAMCET · Maths · Probability
An urn \(A\) contains 3 white and 5 black balls. Another urn \(B\) contains 6 white and 8 black balls. A ball is picked from A at random and then transferred to \(B\). Then, a ball is picked at random from \(B\). The probability that it is a white ball is
- A \(\frac{14}{40}\)
- B \(\frac{15}{40}\)
- C \(\frac{16}{40}\)
- D \(\frac{17}{40}\)
Answer & Solution
Correct Answer
(D) \(\frac{17}{40}\)
Step-by-step Solution
Detailed explanation
Case Ist Let a white ball be transfered from the first bag to the second bag. The probability of selecting white ball from the first bag is \(P_1=\frac{3}{3+5}=\frac{3}{8}\) Now, the second bag has 7 white and 8 black balls. The probability of selecting a white ball from the…
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