TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
When copper metal is treated with cold and dilute nitric acid, it forms
- A \(\mathrm{NO}\)
- B \(\mathrm{N}_2 \mathrm{O}\)
- C \(\mathrm{N}_2 \mathrm{O}_5\)
- D \(\mathrm{NO}_3\)
Answer & Solution
Correct Answer
(A) \(\mathrm{NO}\)
Step-by-step Solution
Detailed explanation
When copper metal is treated with cold and dilute nitric acid. It yields copper nitrate, water and nitric oxide. \(3 \mathrm{Cu}+8 \mathrm{HNO}_3(\) dil. \() \longrightarrow 3 \mathrm{Cu}\left(\mathrm{NO}_3\right)_2+4 \mathrm{H}_2 \mathrm{O}+2 \mathrm{NO}\)
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