TS EAMCET · Chemistry · Alcohols Phenols and Ethers
The major product ' \(Y\) ' in the given sequence of reactions is
\(\mathrm{C}_3 \mathrm{H}_7 \mathrm{OH} \xrightarrow[443 \mathrm{~K}]{\text { Conc. } \mathrm{H}_2 \mathrm{SO}_4} \mathrm{X} \xrightarrow[\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2]{\mathrm{HBr}} \mathrm{Y}\)
- A \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}\)
- B \(\mathrm{CH}_3 \mathrm{CH}(\mathrm{Br}) \mathrm{CH}_3\)
- C \(\mathrm{CH}_3 \mathrm{COC}_6 \mathrm{H}_5\)
- D \(\mathrm{C}_6 \mathrm{H}_5 \mathrm{COBr}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{Br}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{C}_3 \mathrm{H}_7 \mathrm{OH} \xrightarrow{\mathrm{ConcH}_2 \mathrm{SO}_4} \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\left(\mathrm{C}_6 \mathrm{HBr}_5 \mathrm{CO}\right)_2 \mathrm{O}]{ } \\ &…
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