TS EAMCET · Maths · Three Dimensional Geometry
The radius of the circle given by \(\begin{aligned} x^2+y^2 & +z^2+2 x-2 y-4 z-19=0 \ & =x+2 y+2 z+7, \text { is } \end{aligned}\)
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
Equation of the sphere, \(x^2+y^2+z^2+2 x-2 y-4 z-19=0\) ...(i) and equation of plane \(x+2 y+2 z+7=0\) ...(ii) centre of the sphere \((-1,1,2)\) and radius of the sphere \(\begin{aligned} R & =\sqrt{1+1+4+19} \\ & =\sqrt{25}=5 \end{aligned}\) Now, \(p=\) perpendicular distance…
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