TS EAMCET · Chemistry · Hydrocarbons
The major product \((P)\) formed in the below reaction is \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2 \xrightarrow[\mathrm{CCl}_4, 253 \mathrm{~K}]{\mathrm{Br}_2(1 \mathrm{~mol})} P\)
- A \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2-\mathrm{CH}(\mathrm{Br})-\mathrm{CH}_2(\mathrm{Br})\)
- B \(\mathrm{CH}(\mathrm{Br})_2-\mathrm{C}(\mathrm{Br})_2-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2\)
- C \(\mathrm{CH}_2(\mathrm{Br})-\mathrm{CH}(\mathrm{Br})-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2\)
- D \(\mathrm{CH}_2=\mathrm{CH}(\mathrm{Br})-\mathrm{CH}(\mathrm{Br})-\mathrm{CH}=\mathrm{CH}_2\)
Answer & Solution
Correct Answer
(A) \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_2-\mathrm{CH}(\mathrm{Br})-\mathrm{CH}_2(\mathrm{Br})\)
Step-by-step Solution
Detailed explanation
Treatment of alkene with \(\mathrm{Br}_2\) in \(\mathrm{CCl}_4\) solvent gives vicinal dibromides. Bromine added to opposite faces of the double bond (anti addition). \(\mathrm{CH} \equiv \mathrm{C}-\mathrm{CH}_2-\mathrm{CH}=\mathrm{CH}_2\)
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