TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)
Xenon reacts with fluorine at \(873 \mathrm{~K}\) and 7 bar to form \(\mathrm{XeF}_4\). In this reaction, the ratio of xenon and fluorine required is
- A \(1: 5\)
- B \(10: 1\)
- C \(1: 3\)
- D \(5: 1\)
Answer & Solution
Correct Answer
(A) \(1: 5\)
Step-by-step Solution
Detailed explanation
\(\mathrm{XeF}_4\) is obtained by heating a mixture of xenon and fluorine in the molar ratio of \(1: 5\) at \(873 \mathrm{~K}\) and 7 bar pressure in an enclosed nickel vessel for a few hours. The reaction proceeds as…
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