TS EAMCET · Chemistry · Solutions
The freezing point of an aqueous solution containing \(25 \mathrm{~g}\) of ethanol in \(1000 \mathrm{~g}\) of \(\mathrm{H}_2 \mathrm{O}\) is \(\left.K_f=1.86 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]\)
- A \(0.25^{\circ} \mathrm{C}\)
- B \(0.5^{\circ} \mathrm{C}\)
- C \(-1.5^{\circ} \mathrm{C}\)
- D \(-1^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(D) \(-1^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Depression in freezing point is given by \[ \begin{aligned} \Delta T_f & =K_f m . \\ \Delta T_f & =K_f \times \frac{w_B \times 1000}{M_B \times w_A} \\ & =1.86 \times \frac{25 \times 1000}{46 \times 1000}=1.01 \end{aligned} \]…
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