TS EAMCET · Chemistry · p Block Elements (Group 15, 16, 17 & 18)

The correct order of boiling points of $H_{2} O, H_{2} S, H_{2} Se$ and $H_{2} Te$ respectively is

A $H_{2} O > H_{2} S = H_{2} Se = H_{2} Te$
B $H_{2} O < H_{2} S < H_{2} Se < H_{2} Te$
C $H_{2} O > H_{2} S > H_{2} Se > H_{2} Te$
D $H_{2} O > H_{2} Te > H_{2} Se > H_{2} S$

Verified Solution

Answer & Solution

Correct Answer

(D) $H_{2} O > H_{2} Te > H_{2} Se > H_{2} S$

Step-by-step Solution

Detailed explanation

All the elements of Group 16 form hydrides of the type H2E (E = O, S, Se, Te, Po). Their acidic character increases from H2O to H2Te. Boiling point depends on the size and intermolecular forces. As the size of the central atom increases boiling point should increase,but H2O has…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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The correct order of boiling points of H2O,H2 S,H2Se and H2Te respectively is

Step-by-step Solution

The correct order of boiling points of $H_{2} O, H_{2} S, H_{2} Se$ and $H_{2} Te$ respectively is