TS EAMCET · Chemistry · Structure of Atom

For an electron in the d-orbital, the orbital angular momentum is

A $\frac{h}{2 π}$
B $\frac{\sqrt{2} h}{2 π}$
C $\frac{\sqrt{6 h}}{2 π}$
D $\frac{\sqrt{6} h}{2 π}$

Verified Solution

Answer & Solution

Correct Answer

(D) $\frac{\sqrt{6} h}{2 π}$

Step-by-step Solution

Detailed explanation

We Know, For the d-orbital, Azimuthal quantum number l= 2 The formula for determining angular momentum is = ll+1h2π = 22+1h 2π= 6h2π So the orbital angular momentum is equal to 6h2π Hence, option D is correct

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

	List-1(Chemical)		List-2(Use)
A	KOH	I	Coolant
B	Na(l)	II	Antacid
C	Li	III	Electrochemical Cells
D	\(\mathrm{Mg}(\mathrm{OH})_2\)	IV	Absorbent for \(\mathrm{CO}_2\)

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