TS EAMCET · Maths · Indefinite Integration
If \(\frac{x^4+3 x+1}{(x+1)^2(x-1)}=A x+B+\frac{C}{x+1}+\frac{D}{(x+1)^2}+\frac{E}{x-1}\). Then \(A+B+C+D+E=\)
- A \(3 / 2\)
- B \(9 / 2\)
- C \(5 / 2\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(5 / 2\)
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