KCET · Physics · Mathematics in Physics
Two balls are thrown simultaneously in air. The acceleration of the centre of mass of the two balls when in air,
- A depends on the masses of the two balls
- B depends on the speeds of the two balls
- C is equal to \( \mathrm{g} \) (Acceleration due to gravity)
- D depends on the direction of motion of the two balls.
Answer & Solution
Correct Answer
(C) is equal to \( \mathrm{g} \) (Acceleration due to gravity)
Step-by-step Solution
Detailed explanation
Acceleration of centre of mass \(=\frac{m_{1}(-g)+m_{2}(-g)}{m_{1}+m_{2}} \)
\(=-g \frac{\left(m_{1}+m_{2}\right)}{\left(m_{1}+m_{2}\right)}=-g\)
Therefore, acceleration of centre of mass of two balls in air is equal to \( \mathrm{g} \), that is, acceleration due to gravity
\(=-g \frac{\left(m_{1}+m_{2}\right)}{\left(m_{1}+m_{2}\right)}=-g\)
Therefore, acceleration of centre of mass of two balls in air is equal to \( \mathrm{g} \), that is, acceleration due to gravity
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